solve for x: log 64 = 2logx?

Updated on August 6, 2022

solve for x:

log 64 = 2 log x

a.) 1

b.) 5

c.) 8

d.) 4

6 Answers

  • 8. x^2=64. x=8

  • Solve 2 Log X Log 64

  • 2logx-log4=log(3x+16) log x^2 /4 = log (3x+16) x^2/4 = 3x +16 x^2 = 12x + 64 x^2 -12x -64 = 0 (x -16 )(x + 4 ) = 0 Therefore x = 16 or -4

  • c) 8

    log 64/log x =2

    log (base x) 64 =2

    x=8

  • log64 = log x^2

    64 = x^2

    x=8 (root square)

    so answer (c)

  • C.

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