Updated on August 6, 2022
find the number of
a) atoms in one molecule of trinitrotoluene (TNT), CH3C6H2(NO2)3
b) atoms in 1.04×10−3 CH3(CH2)4CH2OH
c) F atoms in 12.30 moles of C2HBrClF3
I tried doing B by using avagadro’s constant but im not getting the right answer.
its 1.04×10^-3 mol
its 1.04×10^-3 mol
2 Answers
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a)
7 atoms C + 5 atoms H + 3 atoms N + 6 atoms O = 21 atoms
b)
(1.04 × 10^−3 mol) × (6.023 × 10^23 molecules/mol) × (21 atoms/molecule) =
1.32 × 10^22 atoms
c) (12.30 moles) × (6.023 × 10^23 molecules/mole) × (3 atoms F/molecule) =
2.222 × 10^25 atoms F
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Tnt Molecule
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